1 Nov
2011
1 Nov
'11
11:04 a.m.
Hi,
You get 0 references, and 3 accesses generated by the super call. The only question if
there should be another access to the implicit variable "this".
The types available in the method signature appear as declaredType, not as a reference.
Cheers,
Doru
On 1 Nov 2011, at 10:46, Andre Hora wrote:
Hello,
I have two simple questions. In the code below:
public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding
enclosingType) {
super(compoundName, scope, enclosingType);
...
}
How many Accesses and References do I have? (do the parameters contain 2 References and
the super 3 Accesses).
Thanks!
--
Andre Hora
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