Hello, I have two simple questions. In the code below: public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { super(compoundName, scope, enclosingType); ... } How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). Thanks! -- Andre Hora _______________________________________________ Moose-dev mailing list Moose-dev(a)iam.unibe.ch https://www.iam.unibe.ch/mailman/listinfo/moose-dev

On Tue, Nov 1, 2011 at 11:04 AM, Tudor Girba <tudor(a)tudorgirba.com&gt; wrote: Hi, You get 0 references, and 3 accesses generated by the super call. The only question if there should be another access to the implicit variable "this". OK. A two months VerveineJ mse does not produce that (just two accesses from other parts of the method, but 0 from the super)

The types available in the method signature appear as declaredType, not as a reference. OK. So if I want to check my providers classes, I need to check Access, Reference, Inheritance, Invocation + check manually the types method signatures (parameters and return if the case)?

Cheers, Doru Thanks Doru, On 1 Nov 2011, at 10:46, Andre Hora wrote: > Hello, > > I have two simple questions. In the code below: > > public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { > super(compoundName, scope, enclosingType); > ... > } > > How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). > > Thanks! > > -- > Andre Hora > > _______________________________________________ > Moose-dev mailing list > Moose-dev(a)iam.unibe.ch > https://www.iam.unibe.ch/mailman/listinfo/moose-dev -- www.tudorgirba.com "One cannot do more than one can do." _______________________________________________ Moose-dev mailing list Moose-dev(a)iam.unibe.ch https://www.iam.unibe.ch/mailman/listinfo/moose-dev -- Andre Hora _______________________________________________ Moose-dev mailing list Moose-dev(a)iam.unibe.ch https://www.iam.unibe.ch/mailman/listinfo/moose-dev

Why 0 references? ClassScope and SourceTypeBinding are 2 references. Alexandre On 1 Nov 2011, at 07:04, Tudor Girba wrote: > Hi, > > You get 0 references, and 3 accesses generated by the super call. The only question if there should be another access to the implicit variable "this". > > The types available in the method signature appear as declaredType, not as a reference. > > Cheers, > Doru > > > On 1 Nov 2011, at 10:46, Andre Hora wrote: > >> Hello, >> >> I have two simple questions. In the code below: >> >> public MemberTypeBinding(char[][] compoundName, ClassScope scope, SourceTypeBinding enclosingType) { >> super(compoundName, scope, enclosingType); >> ... >> } >> >> How many Accesses and References do I have? (do the parameters contain 2 References and the super 3 Accesses). >> >> Thanks! >> >> -- >> Andre Hora >> >> _______________________________________________ >> Moose-dev mailing list >> Moose-dev(a)iam.unibe.ch >> https://www.iam.unibe.ch/mailman/listinfo/moose-dev > > -- > www.tudorgirba.com > > "One cannot do more than one can do." > > > > > _______________________________________________ > Moose-dev mailing list > Moose-dev(a)iam.unibe.ch > https://www.iam.unibe.ch/mailman/listinfo/moose-dev -- _,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;: Alexandre Bergel http://www.bergel.eu ^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;. _______________________________________________ Moose-dev mailing list Moose-dev(a)iam.unibe.ch https://www.iam.unibe.ch/mailman/listinfo/moose-dev