3 Feb
2011
3 Feb
'11
6:30 p.m.
not much to do with the real topic, but just wanted to nastily point out that this is not
a regular expression. :-)
You can specify that you want a particular character repeated (a+), or that you want
anycharacter several repeated (.+)
But I believe regular expression don't allow you to say whatever character comes may
be repeated and only this one ...
nic nitpicking
----- Mail original -----
De: "Lukas Renggli"
<renggli(a)gmail.com>
À: "Moose-related development" <moose-dev(a)iam.unibe.ch>
Envoyé: Jeudi 3 Février 2011 18:00:18
Objet: [Moose-dev] Re: PetitParser, same character multiple times
If you know what you do then parsers can have side-effects:
| head tail char |
head := #any asParser ==> [ :c | char := c ].
tail := PPPredicateObjectParser
on: [ :c | char = c ]
message: 'same expected'.
parser := head , (tail min: n - 1).
Alternative you can modify the grammar itself on the fly:
| head tail |
head := #any asParser ==> [ :c | tail setParser: c asParser. c ].
tail := PPDelegateParser new.
parser := head , (tail min: n - 1).
Cheers,
Lukas
On Thursday, 3 February 2011, Tudor Girba <tudor.girba(a)gmail.com>
wrote:
As far as I understand, you would want something
that parses any of
the following:
"aa"
"bb"
"cc"
"dd"
The simplest way would be something like:
($a asParser , $a asParser) / ($b asParser , $b asParser) ...
The problem is that this will result in many objects and redundant
checks.
I think I would implement it as a specialization of
PPPredicateSequenceParser in which you store the first element, and
add the extra condition that any of the following elements must be
the same.
Cheers,
Doru
On 3 Feb 2011, at 14:23, sback wrote:
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$a asParser min: n
is fine for one character, but what if I want to specify that I
want
any character, or digit, repeated at least n times?
I could do:
($a asParser min: n) / ($b asParser min: n) / ...
but that would be a bit ugly :)
Thanks
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